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zalisa [80]
4 years ago
9

JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw

een the two tangents
Mathematics
1 answer:
luda_lava [24]4 years ago
3 0

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the 
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Juan rides his bike 30 miles in 8 hours. At this rate how many miles does he ride his bike
irinina [24]

Answer:

answer is 7.5 miles

Step-by-step explanation:

30/8=3.75 mi in one hour

3.75*2=7.5 miles in 2 hours

hope it helps

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3 years ago
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3 years ago
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Evaluate 23x-1 for x = 1. 1 4 7 8
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 so 23x-1 becomes

23(1.1478)-1

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4 years ago
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Please help , this will really help my grade!!!
Sauron [17]

Step-by-step explanation:

Because 3x+8 is not equal to 3x-5

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4 years ago
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A swim team must be chosen from 12 candidates. What is the greatest number of different 3-person teams that can be chosen?
grin007 [14]
<h3>Answer: 220 combinations</h3>

==========================================

Explanation:

We have 12*11*10 = 1320 permutations possible. This is where order matters. However, order does not matter with swim teams as there are no positions or ranks. All that matters is the group overall (rather than any individual in the group).

Consider the set {A,B,C}. We have 3*2*1 = 6 ways to arrange this set of letters. When considering a permutation, there are 6 permutations but only 1 combination since order doesnt matter and ABC is the same as BAC. Therefore, we divide 1320 over 6 to get the final answer of 1320/6 = 220.

---------

You can use the combination formula with n = 12 and r = 3. Doing so will give the following:

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_{12} C _3 = \frac{12!}{3!*(12-3)!}\\\\_{12} C _3 = \frac{12!}{3!*9!}\\\\_{12} C _3 = \frac{12*11*10*9!}{3!*9!}\\\\_{12} C _3 = \frac{12*11*10}{3!}\\\\_{12} C _3 = \frac{12*11*10}{3*2*1}\\\\_{12} C _3 = \frac{1320}{6}\\\\_{12} C _3 = 220\\\\

As you can see, we get the same result and note how 1320/6 is also present as well.

8 0
4 years ago
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