Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
The answer would be 8 ^-5
The probability of choosing two yellow marbles = 5/26
Step-by-step explanation:
Step 1 :
Given
Total number of marbles in the bag = 13 marbles
Number of yellow marbles = 6.
We choose 2 marbles from the bag without replacing and need to determine the probability that both are yellow.
Step 2 :
Probability of finding yellow marble in the first try = Number of yellow marbles / Total number of marbles = 
Once the yellow marble is selected we have 5 yellow marbles among 12 remaining marbles in the bag.
Probability of finding yellow marble in the second try = Number of yellow marbles / Total number of marbles = 
Step 3:
P(yellow in first 2 tries) = P(yellow in first try) * P(yellow in second try)
P(yellow in first 2 tries) = 
= 
Step 4:
Answer:
The probability of choosing two yellow marbles = 5/26
Answer: 33 degrees
Step-by-step explanation:
See paper attached. (:
