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3 years ago

7

An art gallery has 18 paintings and 4 photographs displayed in equal rows on the wall, with the same number of each type of art

in each row. What could be the number of rows?

2 answers:

NNADVOKAT [17]3 years ago

4 0

18 divided by 4 this equals 4 with a remainder of 2 so i guess the 2 go in another row

m_a_m_a [10]3 years ago

3 0

Divide 18 by 4 and you will get the answer

Hope this helps :)

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exis [7]

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5 0

3 years ago

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Can someone help me answe this last quiz thank you

nlexa [21]

Answer:

225

Step-by-step explanation:

5^2 * 3^2

(5 * 5) * (3 * 3)

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225

6 0

3 years ago

Read 2 more answers

6 children and 2 adults are going to the circus, children tickets are on sale, half the price of adult tickets totaling $54. How

inna [77]

Answer:

Price of 1 child ticket is $5.4

Price of 1 adult ticket is $10.8

Step-by-step explanation:

Given:-

6 children and 2 adults are going for circus.

Children ticket is half the price of adult ticket.

Total ticketing cost =$54

To find:-

Cost of 1 child ticket=?

Cost of 1 Adult ticket=?

Solution:-

Let price of 1 child ticket be x and price of 1 adult ticket be y,

therefore from the given data we get 2 equations,

$6x+2y=54$ -----------------------------------(1)

$x=\frac{1}{2} y$ --------------------------------(2)

Now, substituting the value of x from equation 2 in equation 1,

$6x+2y=54$

$6(\frac{1}{2} y)+2y=54$

$\frac{6}{2}y+2y=54$

$3y+2y=54$

$5y=54$

$\therefore y=\frac{54}{5}$

$\therefore y =10.8$ ------------------------(3)

Now, substituting the value of y from equation 3 in equation 2,

$x=\frac{1}{2} y$

$\therefore x=\frac{1}{2} \times 10.8$ ------------(from equation 3)

$\therefore x=\frac{10.8}{2}$

$\therefore x=5.4$ ----------------------(4)

As, x is price of 1 child ticket and y is price of 1 adult ticket,

Therefore price of 1 child ticket is $5.4 and price of 1 adult ticket is $10.8

7 0

3 years ago

Grant pays 10 cents per minute plus $5 per month for telephone long distance. Write an algebraic expression for m minutes of lon

dolphi86 [110]

The question is asking for the amount of minutes Grant can possibly use in a month. So to <span>algebraically express this, the equation, </span>0.10 m+5=$ sums it up.

5 0

3 years ago

SOLVE EACH SYSTEM USING SUBSTITUTION

NNADVOKAT [17]

1. since the equations equal each other
2x+19=x+7
-x -x
x+19=7
-19 -19
x= -12
sub into y= x+7
y= -12+7
y= -5

2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0

2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
-39/2 -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10

3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
-5 -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17

4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
-9 -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9

3 0

3 years ago