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3 years ago

Plszzz help me asap schools done i need help pls hurry

Mathematics

2 answers:

Annette [7]3 years ago

7 0

Answer:

1. L=length W=width

(i dont know 2)

3. area

(let me know if this helps)

Vinil7 [7]3 years ago

5 0

For #2 I think the answer is perimeter because that’s the formula used for it.

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Answer:

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3 years ago

Kayla wants to fence in a rectangular dog pen that is 30 ft by 40 ft How would you use wha

castortr0y [4]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the dimension of the dog pen = 30 ft by 40 ft.

Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :

Area of rectangle = Length * width

Area = 40 * 30

Area = 1200 ft²

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3 years ago

Don has 4 pieces of pipe . Each piece is 2 feet inches long . If Don joins the pieces end to end to make one long pipe , how lon

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years

elena55 [62]

Answer:

$\Delta C=-5t^2-250$

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

$C=-5t^2+750$

The average cost of a computer in the year 2008 is given as:

$C=-10t^2+500$

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

$\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250$

Therefore, the difference in the costs for a computer between 2008 and 2000 is $\Delta C=-5t^2-250$

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4 years ago

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Answer:

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