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2 years ago

Helllkkklppppppp plzzzzzzzzz

Mathematics

1 answer:

cupoosta [38]2 years ago

8 0

Answer:

4. 28 sq. inch

Step-by-step explanation:

First, Area of the square = l² = 2² = 4

Area of the triangle = 1/2 x b x h

= 1/2 x 2 x 6

= 6

Total surface area = Area of square + 4 x area of triangle

= 4 + 4 x 6

= 28

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Which statements about the graph of the function f(x) = -2- 4x + 2 are true? Select three options

soldi70 [24.7K]

Answer:Its B,C, and E man

Step-by-step explanation:

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2 years ago

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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

Help for brainlist :)))

SVETLANKA909090 [29]

Answer:

dear option C (2,4,6) is correct for this question

as,

domain = is all set of input values

and

range = is all set of output value

hope this answer helps u dear!

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2 years ago

A data set is made up of these values.

Roman55 [17]

The correct answer is B

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2 years ago

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NISA [10]

Answer:

An improper integral is the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or in some instances as both endpoints approach limits

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3 years ago

Helllkkklppppppp plzzzzzzzzz​

Helllkkklppppppp plzzzzzzzzz