Answer:
y=3/2x+1
Step-by-step explanation:
y-4= -⅔(x-6)
y-4=-⅔x+4
y=-⅔x+4+4
(equation of line 1) y= -⅔x+8 gradient= -⅔
(line 2)gradient=3/2
note* the gradients of perpendicular lines multiplied result to -1
gradient=<u>y²-y²</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>
<u> </u><u> </u>2. x+2
multiply both sides by 2(x+2)to remove the denominators
3(x+2)=2(y+2)
3x+6=2y+4
3x+6-4=2y
3x+2=2y
divide all sides by 2
3/2x+1=y
y=3/2x+1
9xy2-6x2y+5x3. Change every sign in the equation as if you were multiplying each part by -1.
Let the number of girls be x and the number of boys be y
The number of boys is the same as the number of girls.
x = y
The number of boys is twice the number of girls when 8 girls left.
2(x - 8) = y
x = y ---------------- (1)
2(x - 8) = y -------- (2)
Sub (1) into (2)
2(y - 8) = y
2y - 16 = y
2y - y = 16
y = 16
There were 16 boys and 16 girls initially.
16 + 16 = 32
There were a total of 32 students in the class initially.
Answer:
Step-by-step explanation:
2/3*(-2/1)
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Answer:
16 cm
Step-by-step explanation:
x+x
8+8
16 cm
therefore 16 cm must be the value of x be in order for the figures below to be similar
