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Valentin [98]
2 years ago
7

What is the area of the shaded sector? (Round to the nearest tenth) 10 38

Mathematics
1 answer:
masya89 [10]2 years ago
5 0

Answer:

33.1

Step-by-step explanation:

First you need to find the area of the circle. The radius is 10 which means that the area is 314. Since a circle has 360 degrees, and the shaded area is 38 degrees, you need to divide 314 by 360 which is 0.87. Then multiply by 38 because the shaded sector is 38. 0.87 x 38 = 33.1.

That is the answer.

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An employee worked for 8 hours on 2 days, 6 hours on 1 day, and 4 hours on 2 day
choli [55]

Answer:

A) 6.0

Step-by-step explanation:

First, total amount of hours, since average is sum of the numbers by how many numbers there is.

Day 1=8x2 hr

Day 2=6x1 hr

Day 3=4x2 hr

which is, 16+6+8=30

then divide 30 by how many days there is, which is 5 days.

30/5=6

5 0
2 years ago
What Is The Surface Area Of this triangular prism? The Base Of Each Triangle 42m And the height of the triangular base is 20m. (
ehidna [41]

Answer:

The surface area is 2,440\ m^{2}

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The surface area of a triangular prism is equal to

SA=2B+PH

where

B is the area of the triangular base

P is the perimeter of the triangular face

H is the height of the prism

<em>Find the area of the base B</em>

B=\frac{1}{2}(42)(20)=420\ m^{2}

<em>Find the perimeter of the base P</em>

P=(42+29+29)=100\ m

we have

H=16\ m

substitute the values

The surface area is

SA=2(420)+100(16)=2,440\ m^{2}

8 0
3 years ago
What is 453-259 with your work bring shown
photoshop1234 [79]
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Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
Makovka662 [10]

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

6 0
2 years ago
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Serjik [45]
Y= 40x+ 50 (i need 20 characters to post this so ignore)
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3 years ago
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