Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Hope you could understand.
If you have any query, feel free to ask.
Fraction is used to rename 5/6
Answer:
Option A.
f(x) = -4*sin((1/3)*t + (π/6)) + 3
Step-by-step explanation:
We can easily solve this problem by using a graphing calculator or plotting tool.
The function is
f(t) = a*sin (b*t +c) + d
Please, see attached picture below.
By looking at the picture with all the possible cases, we can tell that the correct option is A.
The function has a period of T = 6π
Max . Amplitude = 7
Min . Amplitude = -1
The distributive property means to distribute the number being multiplied by the numbers in the parentheses.
In this case, (v+12) is being multiplied by 10.
To solve this, you simply have to multiply 10 by each term inside the parentheses.
That means it would be (v•10)+(12•10).
(v•10) is equal to 10v, since v is the variable and we don't know its value.
(12•10) is equal to 120.
So by using the distributive property we can find that (v+12)10 = 10v+120.