If H is the circumcenter of triangle BCD, find each measure. CD, CE, HD, GD, HG, HF

Mathematics

1 answer:

Levart [38]3 years ago

7 0

Answer:

H is the circumcenter of triangle BCD

CD = 2FD = 2*32 = 64
CE = BE = 26
HD = HC = 33
GD = 1/2BD = 1/2(58) = 29
HG = √HD ²-GD² = √33²-29² = 2√62 ≈ 15.75
HF = √HD ²-FD² = √33²-32² =√65 ≈ 8.06

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