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mina [271]
2 years ago
10

It takes serina 0.25 hours to drive to school. her route is 16.5 km long. what is serena’s average speed on her drive to school

Mathematics
1 answer:
Lelu [443]2 years ago
7 0
Speed equals distance over time.

16.5 km/ 0.25 hrs= 66 km/hr

Final answer: 66 km/hr
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Which graph shows the solution to the following inequality? 4d-6<18
Nadusha1986 [10]

Answer: C

<u>Step-by-step explanation:</u>

4d - 6 < 18

<u>      +6</u>   <u>+6 </u>

4d      < 24

    \frac{4d}{4} < \frac{24}{4}

       d < 6

Graph: ←----------------o 6

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3 years ago
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Greatest common factor of 7 and 49
valina [46]

Answer:

7

Step-by-step explanation:

The greatest common factor or GCF of 7 and 49 is 7 because 7 is the highest number that can go into both numbers 7 and 49. No other number can go into those numbers except 7.

3 0
3 years ago
A teacher collects data on the number of hours, s, his students spend studying and the number of hours, t, they spend watching T
Sidana [21]
Since there is a negative correlation, evident by the negative slope of the equation of the line given to be -0.5, if we take t as 0, we get an equation of,
                                            s = 3.6
This means that if a student does not watch television, he or she spends a maximum of 3.6 hours studying. 
5 0
3 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
Solve x^2 – 7x = -13.
lara31 [8.8K]

Answer:

No solutions I think

Step-by-step explanation:

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