Can anyone help please! Ixl geometry
1 answer:
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Answer:
Discriminant is positive.
Step-by-step explanation:
From the given graph,
Vertex of the parabola = (-3, -2)
y - intercept of the parabola = (0, 1)
Vertex form of a parabola opening upwards is,
y = a(x- h)² + k
Here (h, k) is the vertex.
By substituting the values of the vertex in this equation.
y = a(x + 2)² - 3
Since this parabola passes through (0, 1)
1 = a(0 + 2)² - 3
a =
a = 1
So the equation of the parabola will be
y = (x + 2)² - 3
y = x² + 4x + 4 - 3
y = x² + 4x + 1
Here a = 1, b = 4 and c = 1 (comparing with standard quadratic equation y = ax² + bx + c)
Discriminant of a quadratic equation is represented by,
(b² - 4ac)
Therefore, the value of discriminant = (4)² - 4(1)(1)
= 16 - 4
= 12
Therefore, discriminant of the given graph is positive.