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IRINA_888 [86]
3 years ago
15

What is the solution of this system of linear equations? y = 2x - 3 2x =y-3 Click on the coordinate grid below to graph the line

s. Infinitely many solutions 10 9 8. no solution 7 6 5 (0, -3) 4 3 2 1 (0, 0) X 0 -6 -7 -5 7 -10 -4 -2 5 -3 6 8 10 -1 -2 -3 -5 -67 -7+ -9+ -10​

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Answer:

the solution is the purpose I love the best part is to watch it s dark blue in a bit of a drive and we will be there by the money for it and only and not the case then we are good

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Sustituir. 20c + 15r + 75p + 50e​
AVprozaik [17]

Answer:

8c - 7r + 10p - 20e

Step-by-step explanation:

Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

Open bracket

20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e

Collect like terms

= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e

= 8c - 7r + 10p - 20e

3 0
3 years ago
(Please help HURRY!) (Don't delete this!) (I WILL GIVE BRAINY!)
ipn [44]
1. A or B

2. C

3. I think B
4 0
3 years ago
Read 2 more answers
2. A bakery makes 40 different flavors of muffins. 25% of the flavors have chocolate as
oksano4ka [1.4K]

Answer:

2. 10 muffins with chocolate 30 without chocolate

Step-by-step explanation:

6 0
2 years ago
Can you do this 3(2x-6)-7x+4?
Serjik [45]
3(2x-6)-7x+4
3*2x=6x. 3*-6=-18
-7x+6x=-1x. -18+4=-14
-1x/-1=x. -14/-1=14
X=14
7 0
3 years ago
A major retail clothing store is interested in estimating the difference in mean monthly purchases by customers who use the stor
mixer [17]

Answer:

Critical value is t = 1.9901

Step-by-step explanation:

We are given the results of the sampling :

                                     In-House Credit Card                National Credit Card                    <u>Sample Size</u> :                              32                                                    50

<u>Mean Monthly Purchases </u>:      $45.67                                            $39.87

<u>Standard Deviation </u>:                $10.90                                             $12.47

Also, the managers wished to test whether there is a statistical difference in the mean monthly purchases by customers using the two types of credit cards, using a significance level α of 0.05.

<em>Firstly, we will specify our null and alternate hypothesis;</em>

Let \mu_1 = Mean Monthly Purchases of In-House Credit Card

     \mu_2 = Mean Monthly purchases of National Credit Card

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0  {means that there is no difference in the mean monthly purchases by customers using the two types of credit cards}

Alternate Hypothesis, H_0 : \mu_1-\mu_2\neq 0  {means that there is statistical difference in the mean monthly purchases by customers using the two types of credit cards}

The test statistics that will be used here is <u>Two-sample t-test statistics</u>;

              T.S. = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t_n___1+n_2-_2

where, \bar X_1 = Sample mean Purchases of In-House Credit Card = $45.67

           \bar X_2 = Sample mean Purchases of National Credit Card = $39.87

            s_p = pooled variance

            n_1 = In-house credit card sample = 32

            n_2 = National credit card sample = 50

So, degree of freedom of t-value here is (32 + 50 - 2) = 80

Now, at 0.05 significance level, t table gives critical value of t = 1.9901 at 80 degree of freedom.

<em>Therefore, the critical value assuming the population standard deviations are not known but that the populations are normally distributed with equal variances is t = 1.9901.</em>

4 0
2 years ago
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