So , as we know that the equation of circle with centre at (h,k) and radius r is given by ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ . Now , using same concept in this question ;

${:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{(x+7)^{2}+(y-17)^{2}=19}}}$

This is the required equation of Circle 

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align="absmiddle

Jobisdone [24]

$\dfrac{1}{9} - \dfrac{5}{6}$

Set up

$\dfrac{2}{18} - \dfrac{15}{18}$

Get all fractions to a common denominator which will allow you to subtract them

$\dfrac{2 - 15}{18}$

Subtract numerators

$\boxed{- \dfrac{13}{18}}$

Simplify

4 0

3 years ago

I can’t figure this out could u help me

djyliett [7]

I think it’s B and C. They are the same distance away from 0 but, they are on different sides. Therefore, they are opposites.

8 0

3 years ago