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Zigmanuir [339]
3 years ago
5

7(x – 3) – 5(2x - 4) = 5​

Mathematics
2 answers:
denpristay [2]3 years ago
8 0
-2 is the answer. I hope that helped. Happy New Years, enjoy with your family and friends.
WITCHER [35]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

7x-21-10x+20=5

7x-10x-1=5

-3x=5+1

x=-6/3

x=-2

You might be interested in
On Thursday a local shop sold a combination of 417 hamburgers and cheese burgers. The number of cheeseburgers sold was two times
seropon [69]

Answer:

The number of hamburgers sold was 139 and the number of cheeseburgers  sold was 278.

Step-by-step explanation:

Let

x -----> the numbers of hamburgers sold on Thursday

y -----> the numbers of cheeseburgers sold on Thursday

we know that

x+y=417 ----> equation A

y=2x ----> equation B

Substitute the equation B in equation A and solve for x

x+2x=417

3x=417

x=139

Find the value of y

y=2(139)=278

therefore        

The number of hamburgers sold was 139 and the number of cheeseburgers  sold was 278.

8 0
3 years ago
PLEASE HELP IMAGE ATTACHED!!! the area of this parallelogram is 120mm^2. Find the value of X
Marta_Voda [28]
The area of a parallelogram is the base times the height so:

A=bh, in this case:

A=hx

x=A/h, we are told that A=120mm^2 and h=10mm so

x=120mm^2/10mm

x=12mm
3 0
3 years ago
3sqrt x - 4=5 solve for x
andrezito [222]
3\sqrt{x}-4=5\ \ \ \ |add\ 4\ to\ both\ sides\\\\3\sqrt{x}=9\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\sqrt{x}=3\ \ \ \ |square\ both\ sides\\\\\boxed{x=9}
3 0
3 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
3 years ago
Michael is 3 33 times as old as Brandon. 1 8 1818 years ago, Michael was 9 99 times as old as Brandon.
ASHA 777 [7]

soo are these real math questions? I mean like do your teachers actually ask you these kind of questions or you are making all this up? because they seem to have no answers for them at all



I hope this is a joke tbh

8 0
4 years ago
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