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alexgriva [62]
3 years ago
15

What is the dark web and what is the .onion domain

Computers and Technology
2 answers:
Troyanec [42]3 years ago
7 0
The dark web is a scary place on the internet
Kitty [74]3 years ago
4 0

Answer:

The dark web is the World Wide Web content that exists on darknets: overlay networks that use the Internet but require specific software, configurations, or authorization to access. 

Explanation:

.onion is a special-use top level domain name designating an anonymous onion service, which was formerly known as a "hidden service", reachable via the Tor network.

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I hope this helped!

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4 years ago
Can someone please help me! It’s due Thursday!
Eva8 [605]

Answer:

if the input is zero the out put is 1

Explanation:

because if you think about it if the input was 1 the output would be zero

7 0
2 years ago
Often, a single source does not contain the data needed to draw a conclusion. It may be necessary to combine data from a variety
nlexa [21]

To measure the pollution of a particular river, one must take the sample of the river and take the sample of pure water, then draw the conclusion, it will tell the amount of pollution in the river water.

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6 0
2 years ago
Russian newspaper says U.S. journalism is conducting 'experiments' to introduce fast-growing artificial intelligence technology.
Marina86 [1]

Answer:

Russian newspaper says U.S. journalism is conducting 'experiments' to introduce fast-growing artificial intelligence technology.

Explanation:

Artificial intelligence (AI) is a wide-ranging tool that enables people to rethink how we integrate information, analyze data, and use the resulting insights to improve decision making—and already it is transforming every walk of life. In this report, Darrell West and John Allen discuss AI's application across a variety of sectors, address issues in its development, and offer recommendations for getting the most out of AI while still protecting important human values.

4 0
3 years ago
Read 2 more answers
Write a program to read a list of exam scores given as integer percentages in the range 0-100. Display the total number of grade
Tju [1.3M]

Answer:

import java.util.Scanner;

public class Program

{

  public static void main(String [] Args)

  {

      int totalAGrades = 0, totalBGrades = 0, totalCGrades = 0, totalDGrades = 0, totalFGrades = 0, counter=0,maximum = 0, minimum = 9999, num, total = 0,smallest = 0,largest = 0;

       Scanner in = new Scanner(System.in);

       System.out.println("Enter exam percentage: ");

       System.out.println("Enter a negative examScore: ");

       int examScore = in.nextInt();

       while(examScore > 0)

       {

         counter++;

         if(examScore < 0){          

             break;}  

         else if(examScore > maximum){      

              maximum = examScore;}

         else if(examScore < minimum)   {  

              minimum = examScore;}

         

          total = total + examScore;  

     

          if(examScore <= 50 && examScore>0)

              smallest = examScore;

              if(examScore > 90 && examScore <=100)

              largest = examScore;

         

      if(examScore>=90 && examScore<=100)

          totalAGrades++;

      else if(examScore>=80 && examScore<=89)

          totalBGrades++;

      else if(examScore>=70 && examScore<=79)

          totalCGrades++;

      else if(examScore>=60 && examScore<=69)

          totalDGrades++;

      else if(examScore>=0 && examScore<=59)

          totalFGrades++;

      examScore = in.nextInt();

     

   }

      System.out.println("Total number of scores is = " + counter );

      System.out.println("Total Number of each Letter grade : " + counter);

      System.out.println("Percentage of total for each letter grade : ");

          System.out.println("Total number of A grades = "+ totalAGrades);

          System.out.println("Total number of B grades = "+ totalBGrades);

          System.out.println("Total number of C grades = "+ totalCGrades);

          System.out.println("Total number of D grades = "+ totalDGrades);

          System.out.println("Total number of F grades = "+ totalFGrades);

     

      System.out.println("Lowest exam Score is :"+smallest);

      System.out.println("Highest exam Score is :"+largest);

      System.out.println("Average exam Score = "+ (total / counter));

  }

}  

Explanation:

  • Get the exam information from user as input and run a while loop until examScore is greater than zero.
  • Use conditional statement to check the scores of students and increment the relevant grade accordingly.
  • Finally display all the information including grades and scores.
3 0
3 years ago
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