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fgiga [73]
3 years ago
14

Tom teaches in a high school. He wishes to sort a spreadsheet containing students' marks in various subjects by descending order

of total
marks. While sorting the spreadsheet, what do you do before clicking the Sort option from the menu?
OA
filter the data to sort
OB.
arrange the data alphabetically
O c. select the data to sort
OD.
look up the data to sort
Computers and Technology
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

Select the data to sort

Explanation:

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Black box testing is the practice of writing tests without knowing the implementation of the code you're testing. White box test
Lelu [443]

Answer:

<u>First test:</u> Give a list of disordered numbers to the sorting algorithm an examine if the output is correctly sorted.

<u>Second test:</u> Give a list of ordered numbers to the sorting algorithm an analyze if the output is still correctly ordered.

<u>Third test:</u> Give a list of ordered numbers and some non-numeric values to the sorting algorithm and check how is managed the exception in case of error or if the output is correctly ordered.

6 0
4 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
Universal Containers has the following requirements:• Enable VIP community access once a customer has reached $1 million in reve
Dima020 [189]

Answer:

A. Create a profile that has permissions to the VIP information and assign it to the VIP community users.

Explanation:

Salesforce is a customer rapport management platform that is based on the cloud. There are program applications for sales, marketing and services. The platforms are utilized to achieve an enhanced relationship with customers because they have a better understanding the need of their customers and how to solve their problems by organization and managing their customers' information and interactions.

VIP users will get access to the information they want when there are permissions set for the VIP users. VIP information will be given to the VIP customers in order for them to carry out activities that they need to do to execute their job.

6 0
3 years ago
How can development in ICT be utilized to speed up the development and integration efforts
maw [93]

Answer:

Explanation:

1.  Sustainability and scale

2.  Lack of knowledge

 

3. Pace of change

4.  Funding

5. Changing roles and norms

7 0
4 years ago
Consider bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}. Can you replace #blank# so the code will print a g
Goshia [24]

Answer:

bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}

for bear in bears:

   if bears[bear] == "friendly":

       print("Hello, "+bear+" bear!")

   else:

       print("odd")

Explanation:

A dictionary called bears is given. A dictionary consists of key-value pairs.

You need to check each key-value pairs in bears and find the ones that have "friendly" as value using a for loop and if-else structure. In order to access the values of the dictionary, use the dictionary name and the key (inside the loop, the key is represented as bear variable). If a key has a value of "friendly", print the greeting. Otherwise, print "odd".

6 0
3 years ago
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