answer: C
explanation: because it's the biggest of the given platforms
Answer:
my Answer is: free license
Explanation:
Answer:
presentation
Explanation:
Based on the scenario being described within the question it can be said that we have to be careful of our presentation so we do not date ourselves too badly. Presentation refers to the way we look, dress, and act. Such as the clothes and accessories we wear, the way we style our hair, etc. All done in order to look our best to others.
This is not a computers and technology question but ill still answer it and the answer to this that i think it is ...A ...but i may be wrong
Answer:
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- int num[] = new int[51];
- Scanner input = new Scanner(System.in);
- System.out.print("Number of input: ");
- int limit = input.nextInt();
- for(int i=0; i < limit; i++){
- System.out.print("Input a number (1-50): ");
- int k = input.nextInt();
- num[k]++;
- }
- for(int j=1; j < 51; j++){
- if(num[j] > 0){
- System.out.println("Number of occurrence of " + j + ": " + num[j]);
- }
- }
- }
- }
Explanation:
The solution is written in Java.
Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).
Create a Scanner object and get user entry the number of input (Line 6-7).
Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).
At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).