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prohojiy [21]
3 years ago
5

I need the answer to this quick

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0
70 did not order vanilla frozen yogurt
luda_lava [24]3 years ago
7 0

Answer:

70

Step-by-step explanation:

250 x .28=70

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Please explain this to me.
Nutka1998 [239]

Answer:

  • The value of x is 12 units.

Step-by-step explanation:

<u>We know that:</u>

  • Formula: h² = a² + b²

<u>Let's solve using Pythagoras theorem.</u>

  • => 13² = 5² + x²
  • => 169 = 25 + x²
  • => 169 - 25 = x²
  • => 144 = x²
  • => √x² = √144
  • => x = √144
  • => x = 12

Hence, the value of x is 12 units.

3 0
3 years ago
Please help! 50 POINTS!!!
expeople1 [14]

Answer:

f(x) = 2/3 x +3

Step-by-step explanation:

We know the y intercept ( where it crosses the y axis)  is 3


We can calculate the slope from 2 points (-3,1) and (0,3)

Slope = (y2-y1)/(x2-x1)

         = (3-1)/(0--3)

          = (3-1)/(0+3)

          = (2/3)

The slope is 2/3


Since we know the slope and the y intercept, we can use the slope intercept form

y= mx+b

y = 2/3 x+3

f(x) = 2/3 x +3

5 0
3 years ago
Read 2 more answers
To finance her community college education, Sarah takes out a loan for $3400. After a year Sarah decides to pay off the interest
sdas [7]
She has to pay $170 i think 
5 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 10 boys an
Marysya12 [62]

212345678901234567890

3 0
3 years ago
Read 2 more answers
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