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3 years ago

Can anyone help me with this

Mathematics

1 answer:

trapecia [35]3 years ago

8 0

Answer:

a)$2800 , $0

b)$1600 , $0

c)$2800 , $0

d)$1650 , $0

e)$4400 , $0

f)$1020 , $0

g)$1405 , $0

h)$5400 , $0

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Pleaseeeee answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

Lelu [443]

Answer:

45 miles

Step-by-step explanation:

Use the Pythagorean Theorem. Imagine a line connecting the ends of the right angle you made by driving. It would make a right triangle. You are trying to find the hypotenuse. Use the formula $a^{2} +b^{2} =c^{2}$ . Square 27, or multiply 27 by 27, to get 729. Add this to the square of 36, 1296. So $c^{2}$ = 2025. Find the square root of 2025. $\sqrt{2025}$ = 45. Hope this helped ^^

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3 years ago

Please look at attached image to answer question!!! 15 points!!! Answer both to get BRAINLY!

Mkey [24]

I think the first one is 1/200 and the second is 1/125

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3 years ago

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Please need help thank

babymother [125]

Answer:

Step-by-step explanation:

One member in the graph only went one time which is fewer than two times.

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2 years ago

Is line 1 (1,5) (3,-2) and like 2 (-3,2) (4,0) perpendicular of parallel?

Lera25 [3.4K]

Slope Formula: $\frac{y_2-y_1}{x_2-x_1}$

So remember that perpendicular lines have slopes that are negative reciprocals to each other and parallel lines have the same slope. To find out if they are either parallel or perpendicular, plug the pair of points into the slope formula to find their slopes:

$\textsf{Line 1}\\\\\frac{5-(-2)}{1-3}=-\frac{7}{2}\\\\\textsf{Line 2}\\\\\frac{0-2}{4-(-3)}=-\frac{2}{7}$

Since these slopes aren't the same nor are they negative reciprocals to each other, the lines are neither parallel nor perpendicular.

7 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Solution:

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers