Answer:
10
Step-by-step explanation:
replace x with 2 and you will got the answer...
One revolution is completed when a fixed point on the wheel travels a distance equal to the circumference of the wheel, which is 2π (13 cm) = 26π cm.
So we have
1 rev = 26π cm
1 rev = 2π rad
1 min = 60 s
(a) The angular velocity of the wheel is
(35 rev/min) * (2π rad/rev) * (1/60 min/s) = 7π/6 rad/s
or approximately 3.665 rad/s.
(b) The linear velocity is
(35 rev/min) * (26π cm/rev) * (1/60 min/s) = 91π/6 cm/s
or roughly 47.648 cm/s.
The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.
Answer: equation of the tangent plane is z = 1
Step-by-step explanation:
Given equation
z = e^(-x²-y²) at point (0,0,1)
now let z = f(x,y)
Δf(x,y) = [ fx, fy ]
= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))
now
Δf (0,0) = [ 0, 0 ] = [ a, b ]
equation of the tangent plane therefore will be
z - z₀ = a(x-x₀) + b(y-y₀)
z - 1 = 0(x-0) + 0(y-0)
z - 1 = 0 + 0
z = 1
Therefore equation of the tangent plane is z = 1
