Answer:
Step-by-step explanation:
arc UW=360-(127+133)
=360-260
=100
m<V=1/2×100
=50°
Step-by-step explanation:
z = (x − μ) / σ
z = (65 − 69) / 3.5
z = -1.14
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
100
Step-by-step explanation:
it is a bit unclear to me, what that problem description means.
if I understand it correctly, than z is directly depending on x².
so, z = 16 for x = 2. x² = 4
I pondered a little bit, as there are several possibilities to connect 16 with 4 as a driving factor (e.g. 2⁴ = 16, 4×4 = 16, 12 + 4 = 16).
I decided to go with the simplest interpretation with the usual meaning of "varies" (multiplication) : 4×x²
that would mean
z = 4×x² = 4×5² = 4×25 = 100