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Oduvanchick [21]
2 years ago
8

What is y – 3 = 7 (x – 5) in standard form?

Mathematics
2 answers:
yuradex [85]2 years ago
8 0

Answer:

38=7x-y

Step-by-step explanation:

standard form= Ax+By+C

(y-3=7(x-5))

(y-3=7x-35)+3 to both sides

(y=7x-38) +38 to both sides

(y+38=7x) -y to both sides

38=7x-y

you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form

Charra [1.4K]2 years ago
6 0

Answer:

7x-y=32

Step-by-step explanation:

I really hope this helps! :)

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3 years ago
What is are the solutions to | x+4 |= 3x-5?
bonufazy [111]

Answer:

x = \frac{9}{2}

Step-by-step explanation:

The absolute value always returns a positive value but the expression inside can be positive or negative, that is

x + 4 = 3x - 5 ( subtract 3x from both sides )

- 2x + 4 = - 5 (subtract 4 from both sides )

- 2x = - 9 ( divide both sides by - 2 )

x = \frac{9}{2}

OR

-(x + 4) = 3x - 5

- x - 4 = 3x - 5 ( subtract 3x from both sides )

- 4x - 4 = - 5 ( add 4 to both sides )

- 4x = - 1 ( divide both sides by - 4 )

x = \frac{1}{4}

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions

| \frac{9}{2} + 4 | = | \frac{17}{2} | = \frac{17}{2}

right side = \frac{27}{2} - 5 = \frac{17}{2}

left side = right side , thus x = \frac{9}{2} is a solution

check second solution

| \frac{1}{4} + 4 | = |  \frac{17}{4} | = \frac{17}{4}

right side =   \frac{3}{4} - 5 = -   \frac{17}{4}

right side ≠ left sides, hence not a solution

7 0
3 years ago
Problem 1.1<br> Solve this equation:<br> 2(x + 5) = 3x + 1
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Answer:

x = 9

Step-by-step explanation:

Distribute

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2x+10=3x+1

Subtract 3x from both sides

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Subtract 10 from both sides

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Multiply both sides by -1

x=9

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3 years ago
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Ira Lisetskai [31]

gohead ask a teacher or another site

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