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3 years ago

What is y – 3 = 7 (x – 5) in standard form?

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

Answer:

38=7x-y

Step-by-step explanation:

standard form= Ax+By+C

(y-3=7(x-5))

(y-3=7x-35)+3 to both sides

(y=7x-38) +38 to both sides

(y+38=7x) -y to both sides

38=7x-y

you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form

Charra [1.4K]3 years ago

6 0

Answer:

7x-y=32

Step-by-step explanation:

I really hope this helps! :)

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rewona [7]

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$=-1\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\\\\\=-1 \times -1 \begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\text{R.H.S}\\\\\text{Showed.}$

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