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Oduvanchick [21]
3 years ago
8

What is y – 3 = 7 (x – 5) in standard form?

Mathematics
2 answers:
yuradex [85]3 years ago
8 0

Answer:

38=7x-y

Step-by-step explanation:

standard form= Ax+By+C

(y-3=7(x-5))

(y-3=7x-35)+3 to both sides

(y=7x-38) +38 to both sides

(y+38=7x) -y to both sides

38=7x-y

you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form

Charra [1.4K]3 years ago
6 0

Answer:

7x-y=32

Step-by-step explanation:

I really hope this helps! :)

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Read 2 more answers
A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.
kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis

4 0
3 years ago
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Explanation:
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2 years ago
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