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2 years ago

What is y – 3 = 7 (x – 5) in standard form?

Mathematics

2 answers:

yuradex [85]2 years ago

8 0

Answer:

38=7x-y

Step-by-step explanation:

standard form= Ax+By+C

(y-3=7(x-5))

(y-3=7x-35)+3 to both sides

(y=7x-38) +38 to both sides

(y+38=7x) -y to both sides

38=7x-y

you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form

Charra [1.4K]2 years ago

6 0

Answer:

7x-y=32

Step-by-step explanation:

I really hope this helps! :)

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locate the point on the line segment A (3,-5) and B (13,-15) given that the point is 4/5 of the way from A to B. Show your work

rjkz [21]

Answer:

The coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

Step-by-step explanation:

As the line segment has the points:

A(3, -5)

B(13, -15)

Let (x, y) be the point located on the line segment which is 4/5 of the way from A to B.

Using the formula

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

Here, the point (x , y) divides the line segment having end points (x₁, y₁) and (x₂, y₂) in the ratio m₁ : m₂ from the point (x₁, y₁).

As (x, y) be the point located on the line segment which is 4/5 of the way from A to B, meaning the distance from $A$ to $(x , y)$ is $4$ units, and the

distance from $(x , y)$ to B is 1 unit, as $5 - 4 = 1$ .

Thus

m : n = 4 : 1

Finding x-coordinate:

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$x=\frac{\left(3\right)\left(1\right)+\left(13\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$x=\frac{3\cdot \:1+13\cdot \:4}{4+1}$

$x=\frac{55}{4+1}$ ∵ $3\cdot \:1+13\cdot \:4=55$

$x=\frac{55}{5}$

$\mathrm{Divide\:the\:numbers:}\:\frac{55}{5}=11$

$x=11$

Finding y-coordinate:

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{\left(-5\right)\left(1\right)+\left(-15\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$y=\frac{-5\cdot \:\:1-15\cdot \:\:4}{4+1}$

$=\frac{-65}{4+1}$ ∵ $-5\cdot \:1-15\cdot \:4=-65$

$=\frac{-65}{5}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y=-\frac{65}{5}$

$y=-13$

The x-coordinate = 11

The y-coordinate = -13

Therefore, the coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

7 0

2 years ago

Consider the vectors Bold uuequals=left angle 4 comma 0 right angle4,0 and Bold vvequals=left angle negative 3 comma negative 3

saw5 [17]

Answer:

Angle between the two vectors is 135°

u•v = -12

Step-by-step explanation:

Given two vectors u = (4,0) and v = (-3,-3).

To find the angle between the two vectors we will use the formula for calculating the angle between two vectors as shown;

u•v = |u||v|cos theta

cos theta = u•v/|u||v|

theta = arccos (u•v/|u||v|)

u•v = (4,0)•(-3,-3)

u•v = 4(-3)+0(-3)

u•v = -12

For |u| and |v|

|u| = √4²+0²

|u| = √16 = 4

|v| = √(-3)²+(-3)²

|v| = √9+9

|v| = √18

|v| = 3√2

|u||v| = 4×3√2 = 12√2

theta = arccos(-12/12√2)

theta = arccos(- 1/√2)

theta = -45°

Since cos is negative in the second quadrant, theta = 180-45°

theta = 135°

To get u•v using the formula u•v = |u||v|cos theta

Given |u||v| = 12√2 and theta = 135°

u•v = 12√2cos 135°

u•v = 12√2× -1/√2

u•v = -12√2/√2

u•v = -12

For the diagram of the vectors, find it in the attachment below.

4 0

2 years ago

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Determine whether the function is periodic. If it is, find the period.

densk [106]

9514 1404 393

Answer:

not periodic

Step-by-step explanation:

There is no value p such that f(x) = f(x+p) for all x. Hence. the function is NOT PERIODIC.

_____

It seems possible that subtracting the linear increase would result in a periodic function. Because of the linear increase, there is no left- or right-shift of the function that will map it to itself.

6 0

2 years ago

Write a slope-intercept equation of a line that is parallel to y = 2/3 x -4 and has a y-intercept of 8.

Leokris [45]

Answer:

uuuuuuuguuguguu

Step-by-step explanation:

7 0

1 year ago

Write the point slope form of the equation of the line through the given slope through (5,3) ,slope =-1/5

iren [92.7K]

Answer:

y-3= -1/5(x-5)

Step-by-step explanation:

point slope form is --> y-y,=m(x-x,)

commas represent 1's.

-1/5= m

3=y,

5=x,

3 0

2 years ago

Read 2 more answers