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2 years ago

Solve the following inequality for the variable and graph the solution on the number line.

Mathematics

1 answer:

Likurg_2 [28]2 years ago

5 0

The solved inequality is t > 12.

Divide both sides by 9 to isolate the variable.

9t becomes t, and 108 becomes 12.

We do not flip the sign because we are dividing by a positive.

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A Store-It-All storage facility requires users to enter a four digit code, using numbers 0-9, to get through the gate. You need

Tems11 [23]

Take me the brayniest.i hope it was helpful

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2 years ago

Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam

frutty [35]

Answer:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

Explanation:

Name the variables and build a system of two equations with two unknowns.

1. Variable r: cost of one rose bush

2. Variable g: cost of one bunch of ornamental grass.

3. First equation:

Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

4r + 4g = 68

4. Second equation:

Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

11r + 2g = 115

5. System of equations:

4r + 4 g = 68 equation 1

11r + 2g = 115 equation 2

6. Solve the system

a) Divide the equation 1 by 2:

2r + 2g = 34 equation 1a

11r + 2g = 115 equation 2

b) Subtract equation 1a from equation 2:

11r - 2r = 115 - 34

9r = 81

r = 81 / 9

r = 9

c) Substitute the value of r into the equation 1a:

2(9) + 2g = 34

9 + g = 17

g = 17 - 9

g = 8

7. Conclusion:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

7 0

2 years ago

In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro

postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\$

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

$P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738$

3 0

3 years ago

Need all the help I can get

o-na [289]

7)$25.50×.06=$1.53
$25.50+$1.53=$27.03
8)$66.30×.07=$4.64(actually $4.641 but have to round since it's money)
$66.30+$4.64=$70.94
9)$23.06×.065=$1.50(actually $1.4989 but have to round since it's money)
$23.06+$1.50=$24.56
10)$34.99×.0525=$1.84(actually $1.836975 but have to round since it's money)
$34.99+$$1.84=$36.83
11)$199.99×.0625=$12.50(actually $12.499375 but have to round since it's money)
$199.99+$12.50=$112.49
12)$130.25×.08=$10.42
$130.25+$10.42=$140.37

4 0

2 years ago

Joe has eaten 4/5 of a pizza and Jane has eaten 1/7 how many times more pizza has Joe eaten than Jane

lukranit [14]

Answer
5.6

Explanation
Joe Jane
4/5 1/7

28/35 5/35

28/5 = 5.6
Joe ate 5.6 times more than Jane

6 0

2 years ago