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Stolb23 [73]
3 years ago
12

Pls helppp! tysmmmm!!

Mathematics
1 answer:
Margaret [11]3 years ago
5 0
I believe it would be 29 because a supplementary angle is 2 angles that equal 180 so I would think to do 189-151=29
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A 28 because 7 times four

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3 years ago
Mr. Bennet owns 4 restaurants. The mean number of tables is 30. What could happen to the mean if he buys two new restaurants, on
wariber [46]

Answer:

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3 years ago
Which dimensions cannot create a triangle?
podryga [215]

Answer:

three angles measuring 109º, 25º, and 145º cannot create a triangle

three angles measuring 40º, 70º, and 65º cannot create a triangle

Step-by-step explanation:

<u><em>Verify each dimensions</em></u>

Part 1) three angles measuring 109º, 25º, and 145º

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In this problem we have

109^o+25^o+145^o=279^o

279^o> 180^o

therefore

three angles measuring 109º, 25º, and 145º cannot create a triangle

Part 2) three sides measuring 9 m, 15 m, and 9 m

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the triangle inequality theorem

1) 9+15 > 9 ---> is ok

2) 9+9 > 15 ---> is ok

therefore

three sides measuring 9 m, 15 m, and 9 m can create a triangle

Part 3) three angles measuring 40º, 70º, and 65º

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In this problem we have

40^o+70^o+65^o=175^o

175^o< 180^o

therefore

three angles measuring 40º, 70º, and 65º cannot create a triangle

Part 4) three sides measuring 6 cm, 8 cm, and 10 cm

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the triangle inequality theorem

1) 6+8 > 10 ---> is ok

2) 8+10 > 6 ---> is ok

3) 6+10 > 8 ---> is ok

therefore

three sides measuring 6 cm, 8 cm, and 10 cm can create a triangle

4 0
3 years ago
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