What is the minimum number of 60 passenger buses needed to transport 200 students?
1 answer:
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The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Option B:
Solution:
Take LCM of the denominators and Make the denominators same.
LCM of 16, 320, 1 = 320
All the denominators are same, so you can write in one fraction.
Do cross multiplication.
Add 9280 on both sides of the equation.
Subtract 20x on both sides of the equation.
Let y = f(x).
Hence Option B is the correct answer.