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faltersainse [42]
3 years ago
7

A cell phone company produces 40 defective phones out of every 5000 phones. Another cell phone company produces 30 defective pho

nes out of every 6000 phones. What is the highest number of defective phones do the companies have in common?
Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

10

Step-by-step explanation:

Given that:

Company A:

40 defective out of every 5000

Company B :

30 out of every 6000

To obtain the highest number of defective phones both companies can produce in common :

Factors of :

40 : 2, 4, 5, 8, 10, 20, 40

30 : 2, 3, 5, 6, 10, 15, 30

Hence, highest number of defective phones both companies can produce in common is 10

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andreyandreev [35.5K]

Answer:

24/35

Step-by-step explanation:

1) Convert your mixed number (1 and 1/7) to an improper fraction by multiplying your whole number (1) and your denominator (7) which gives you 7. Then add your numerator (1) to that which gets you 8. Then take the original denominator (7) and turn it into improper where your new numerator is 8 and your denominator stays 7. (If that doesn't make much sense then you can look up how to change mixed numbers into improper fractions.)

2) Multiply your numbers straight across.

8/7 * 3/5

8*3= 24

7*5= 35

24/35  you can't simplify this, so 24/35 is your answer

8 0
3 years ago
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Answer:

1/42

Step-by-step explanation:

consumed

1/2+1/3= 5/6

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6/7-5/6= 1/42

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3 years ago
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Dvinal [7]

The linear approximation to f(x) near x=16 is

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We have

f(x)=\sqrt x\implies f(16)=4

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Then

f(16.2)\approx L(16.2)\iff\sqrt{16.2}\approx\dfrac{16.2}8+2

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3 years ago
Someone help <br> wh ores.
kirill115 [55]

Answer

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Point 2 (5, 20)

Step-by-step explanation:

Since we are given the x values of 2 and 5, substitute them in the equation and you will get 8 and 20.

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Read 2 more answers
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