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lbvjy [14]
3 years ago
12

HELP ASAP 6TH GRADE MATH I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0
It would be letter a
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Someoneeee pleaseeee helpppp me outtttttt!!!!!!!
arlik [135]

Answer:

cos X = \frac{5}{13}

Step-by-step explanation:

simplify 15/39

3 0
3 years ago
Read 2 more answers
Define function. What are five representations of functions? Give an example of each.
IrinaK [193]

Answer:

A function is a relationship between two variables, such that one variable is determined by the other variable.

A function can be represented verbally. For example, the circumference of a square is four times one of its sides.

A function can be represented algebraically. For example, 3x+6 3 x + 6 .

A function can be represented numerically.

A function can be represented graphically.

Step-by-step explanation:

6 0
3 years ago
The sum of two numbers is 40 and their difference is 6.5, what is their product? show work please
Finger [1]
Let b>a, 

a+b=40 so we can say a=40-b

We are told that b-a=6.5, using a found above in the equation gives us:

b-(40-b)=6.5

b-40+b=6.5

2b-40=6.5

2b=46.5

b=23.25, and since  a=40-b

a=40-23.25

a=16.75

So a=16.75 and b=23.25

check...

16.75+23.25=40, 40=40

23.25-16.75=6.5, 6.5=6.5

4 0
3 years ago
5 markers cost $6.55.Which equation would help determine the cost of 4 markers?
Semmy [17]

5 markers -------> $6.55

4 markers -------> x

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4 0
1 year ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
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