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klemol [59]
3 years ago
12

To use Long Division of Polynomials to verify that x = a/b is a zero on a polynomial function P(x), the divisor would be

Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

  D)  bx - a

Step-by-step explanation:

If a/b is a zero, then (x -a/b) is a factor of the polynomial. That is, the value x=a/b will make a factor of the polynomial be zero.

The above factor can be written without fractions by multiplying it by b:

  (bx -a) . . . . matches choice D

__

You can also choose the answer on the basis of which expression becomes zero when x=a/b.

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The scale on a drawing is 1 cm = 4.5 meters. If the length of the drawing is 6.2 cm, what is the actual length in meters?
Nataly [62]

Answer:

I think the awnser is 27.9

Step-by-step explanation:

4.5*6.2=27.9

7 0
3 years ago
Math (will give Brainliest) 1
Zielflug [23.3K]

Answer: Okay! Here is your answer!

Exact form : 41/6

Decimal form : 6.83 (line over the 3)

Mixed number form : 6 5/6

Step-by-step explanation: Substitute the value of the variable into the equation and simplify.

Hope this is what you were looking for and I hope it helps you out! ☺

7 0
3 years ago
Which difference is about 10?
Helga [31]

Option B is the answer.

70.9 - 58.7

4 0
3 years ago
In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma
bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a)=\frac{v-u}{t}

a=\frac{60\times 60\times 60}{4}

a=54\times 10^3 mi/h^2

To reach a speed of 183.58mi/h with an acceleration of 54\times 10^3 mi/h^2

Using equation of motion

v=u+at

183.58=0+(54\times 10^3)t

t=\frac{183.58}{54\times 10^3}

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

s=ut+\frac{1}{2}at^2

5=0+\frac{1}{2}\times 54\times 10^3 \times t^2

t=0.01360 hour

or t=48.98\approx 49 s

7 0
3 years ago
Look at the figure. How can you prove ∆ABD and ∆ACD are congruent?
Levart [38]

Answer:

Options (C)

Step-by-step explanation:

For the congruence of the triangles ΔADB and ΔADC,

                Statements                             Reasons

1). AB ≅ AC                                   1). Given

2). AD ≅ AD                                 2). Reflexive property

3). ∠BAD ≅ ∠CAD                       3). Given

4). ΔABD ≅ ΔCAD                       4). SAS postulate

Therefore, Options (C) will be the correct option.

7 0
3 years ago
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