Question

Suppose that goats have one gene that codes for color, where a is brown and a is white. the goats also have another gene that codes for height, where b is tall and b is short. if these two genes are unlinked, what is the probability that a cross between aa bb × aa bb parents will produce two out of six offspring that are brown and short

Answer 1

Using a genetic cross, we can look at the following A = brown a = White, B = Tall, b = small With the capital letters being the dominant allele A a B AB aB b Ab ab The allele we are looking for is Ab which as 1/4 chance To work out how many are in 2/6 also (1/3) we do 1/4 x 1/4 x 1/4 = 1/64

Answer 2

When the goats have one gene that codes for color, where A is brown and a is white. The goats also have another gene that codes for height, where B is tall and b is short. If these two genes are unlinked, then the probability that a cross between AABB x aabb parents will produce brown and short is 1/16.

Further explanation

Cross

When we cross two goats of AABB and aabb gene pair then in first filial generation all the individual has AaBb genes and will be brown and tall. But when the members of first filial generation are crossed with one another (cross between AaBb x AaBb) then the progeny of second filial generation will have the both parental combinations along with new combinations with a phenotypic ratio 9:3:3:1 brown and tall 9, brown and short 3, white and tall 3, white and short 1. The probability of white and short will be ¼ x ¼ = 1/16 because the probability of white goats is 1/4 and that of short goats is also ¼.  

Probability

It is the chance of an event to occur. While the joint probability is the product of the individual probabilities of each event.  

Answer details

Subject: Biology

Level: High school

Keywords

• Cross
• Probability

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