So we’ll just use “R” and “r” for this example. If the mother AND father are heterozygous, then both of their genotypes are “Rr” if you work out the lumber square or use the foil method, the box would look like this: RR on top left, Rr on top right, Rr on bottom left, and rr on bottom right. So the genetic probabilities, using four as the sum would be 1:2:1
I would think that is the red blood cell. I could be wrong so correct me if I am.
Only individuals with an aa genotypewill express a recessive trait; therefore, offspring must receive onerecessive allele from each parent to exhibit a recessive trait. One example of a recessive inherited trait is a smooth chin, as opposed to a dominant cleft chin.
Answer:
When T T and t t are crossed, the offspring will be Tt, Tt, Tt, and Tt receiving one trait from each pea plant. Each offspring has the dominant trait, T so it is certain that each pea will show the dominant trait. Thus, the frequency of the dominant trait will be one.
