Help me please it’s important !

Marina CMI [18]

$y = 3tan(x + 30)$
$y = 3(\frac{tan(x) + tan(30)}{1 - tan(x)tan(30)})$
$y = \frac{3(tan(x) + tan(30))}{1 - tan(x)tan(30)}$
$y = \frac{3(tan(x)) + 3(tan(30))}{1 - tan(x)tan(30)}$
$y = \frac{3tan(x) + 3tan(30)}{1 - tan(x)tan(30)}$

5 0

3 years ago

Find the value of each of the following.Increase 60 by 35 percent

daser333 [38]

Answer:

the new value is 81.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Graph: f(x) = -3sin (x/2 - π/4)

charle [14.2K]

This sine function has the form y = f(x) = a sin (bx + c), where |a| is the amplitude, b is the frequency, and c determines the phase shift.

The period of this sine curve is 2 pi/b, or (in this problem) 2 pi/(1/2).

The phase shift of this curve is -c/b, or -(pi/4)/(1/2). Simplify this.

The amplitude is |-3|, or just 3.

Draw a set of coordinate axes. Draw light horizontal lines through y=3 and y=-3. These are the max and min. values of this sine function.

Plot the phase shift on your x-axis.

Your sine function will begin at (phase shift value, 0) and continue for one period. Add the period to the phase shift value. Draw a sine curve beginning and ending at these two x-values.

I encourage you to share your calculations and to sketch the graph described here. Then I could give you more specific feedback on your work. Good luck!

3 0

3 years ago

The price of an all-access ticket to the fair is $42.99 before tax. Roland bought the all-access ticket for 40% off. He then pai

Ulleksa [173]

Answer:

18.39972

Step-by-step explanation:

40% of 42.99 is 17.196

plus a 7% of sales tax would be 18.39972

5 0

4 years ago

Read 2 more answers

1

Tcecarenko [31]

Answer:

It is not possible for the student to receive an A grade in the class.

It is possible for the student to receive a B grade in the class.

Step-by-step explanation:

We are given that in the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each.

A student has received homework scores of 7, 8, 7, 5, and 8, and the first two exam scores are 81 and 80.

Firstly, we will calculate how many points have been scored by the student.

Number of possible points = 350

The points scored by the student in homework = 7 + 8 + 7 + 5 + 8 = 35 points.

The scores of the student on the two exams = 81 + 80 = 161 points

So, the total points scored by the students = 35 + 161 = 196 points.

As it is given in the question that if the grade percentage is 0.9 or higher then the student will get an A, i.e;

If the total possible points are 350 points; $90\% \text{ of } 350 = \frac{90}{100}\times 350 = 315 \text{ points}$

This means that the student must have to score 315 points to get an A grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 < 315, this means that it is not possible for the student to receive an A in the class.

Also, it is given in the question that if the grade percentage is between 0.8 and 0.9 the student will get a B, i.e, the student must obtain a minimum of 80% to get B grade.

If the total possible points are 350 points; $80\% \text{ of } 350 = \frac{80}{100}\times 350 = 280 \text{ points}$

This means that the student must have to score a minimum of 280 points to get a B grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 > 280, this means that it is possible for the student to receive a B grade in the class.

3 0

3 years ago