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Ne4ueva [31]
3 years ago
5

How do i graph 3tan(x+30)

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
y = 3tan(x + 30)
y = 3(\frac{tan(x) + tan(30)}{1 - tan(x)tan(30)})
y = \frac{3(tan(x) + tan(30))}{1 - tan(x)tan(30)}
y = \frac{3(tan(x)) + 3(tan(30))}{1 - tan(x)tan(30)}
y = \frac{3tan(x) + 3tan(30)}{1 - tan(x)tan(30)}


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Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 114
NISA [10]

Answer:

Step-by-step explanation:

Represent the length of one side of the base be s and the height by h.  Then the volume of the box is V = s^2*h; this is to be maximized.

The constraints are as follows:  2s + h = 114 in.  Solving for h, we get 114 - 2s = h.

Substituting 114 - 2s for h in the volume formula, we obtain:

V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)

This is to be maximized.  To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:

dV

----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2

ds

Simplifying this, we get dV/ds = -4s^2 + 114s = 0.  Then either s = 28.5 or s = 0.

Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in

and the volume is V = s^2(h) = 46,298.25 in^3

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3 years ago
What can you conclude about the tangent lines and the diameter of a circle?
svetlana [45]

Answer:

B. perpendicular Hope this helps!

6 0
3 years ago
In the diagram below, ΔABC is inscribed in circle P. The distances from the center of circle P to each side of the triangle are
4vir4ik [10]
Supposing the sides with 6 and 8 is a right angle, you can create a new line from C and P, and find the length using the equation of a²+b²=c² or 6²+8²=c², with c equaling the radius of the circle.

After finding c, you will have to find the length from C to the midpoint of AC, using the same equation a²+b²=c². If both the lengths of C to the midpoint of AC, and A to the midpoint of AC are equal, you can do b+b to find the length of AC.

Using the same approach, you can find AB. Hope this makes sense, if not, I can clarify more.
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3 years ago
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Vikentia [17]

Answer:

  A) The model exists: f(x) = -3x^2 +4x -4

Step-by-step explanation:

A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.

Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.

The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...

  f(x) = -3x^2 +4x -4

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Expalin what the vertical line test is and it used ?
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You use the vertical line test to see if a function is relation is a function

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