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Ne4ueva [31]
3 years ago
5

How do i graph 3tan(x+30)

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
y = 3tan(x + 30)
y = 3(\frac{tan(x) + tan(30)}{1 - tan(x)tan(30)})
y = \frac{3(tan(x) + tan(30))}{1 - tan(x)tan(30)}
y = \frac{3(tan(x)) + 3(tan(30))}{1 - tan(x)tan(30)}
y = \frac{3tan(x) + 3tan(30)}{1 - tan(x)tan(30)}


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Answer:

Step-by-step explanation:

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So in order the trinomial a perfect square we need

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The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

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<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

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<u>Question #8</u>

The vertex of the graph is

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So, we have:

y = a(x - 1)^2 - 2

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a = -1

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y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

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Answer:

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