Answer:
8280 cal
Step-by-step explanation:
Q=mc(delta)T
Q=1200(0.115)(-60)
Q=8280 cal
I used 1200 g instead of 1.2 kg
P = R - E
600 = 120x - 300
The value of x from the equation is 7.5. The answer therefore for the first question is $7.5. Then, the number of kilogram of cumin she needs to sell to cover the expenses is $300/$7.5 and that is equal to 40.
I tried my best hope this helps
Q1=3 Q2[median]=12 Q3=14 and the IQR is 11
Greater then or less then
