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alexgriva [62]
3 years ago
7

In scientific notation,the distance is m×10n where is ..and n is..

Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0
Sorry knoww the answer not
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12b−15>21?? How is this done? Need help ASAP
dangina [55]
12b-15>21
+15 +15

12b > 36
----- ----
12 12

b = 3
3 0
4 years ago
Read 2 more answers
Y - 5 = -2x - 4<br><br>Write in simpilest form.
Romashka-Z-Leto [24]
Y - 5 = -2x - 4

Add 5 on both sides.
y = -2x + 1

y = -2x + 1 is in simplest form.
7 0
4 years ago
Fill in the missing statement and reason in the proof of the Alternate Exterior Angles Theorem.
ludmilkaskok [199]

Answer:

∠EGB and ∠AGF are congruent;

Transitive Property of Equality

Step-by-step explanation:

The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other

Vertical angles are congruent i.e their measures are equal

Look at the attached graph

Given:

AB // CD

E , G , H , F are col-linear

The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD

∵ AB and EF intersected at point G

∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem

When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent (  vertical angle theorem)

∵ AB // CD and EF is a transversal

∴ m∠AGF = m∠CHF (corresponding angles theorem)

Transitive Property of Equality:  if one angle is equal to two other angles, then the two other angles are equal

 Therefore, If a = b and b = c, then a = c

∵ m∠EGB = m∠AGF

∵ m∠AGF = m∠CHF

∴ m∠EGB = m∠CHF (transitive property theorem)

 ∠EGB and ∠AGF are congruent; Transitive Property of Equality

4 0
3 years ago
Read 2 more answers
WILL MARK BRANLIEST!!!!!!!!! HELP ASAP!<br><br> Add. Write your answer in simplest form. 3/8+ 2/5
Art [367]

Answer:

31/40

Step-by-step explanation:

3/8=15/40

2/5=16/40

15/40+16/40=31/40

6 0
3 years ago
Read 2 more answers
There is 1500 ft of fencing available to make 6 identical pens. Find the maximum area for EACH pen (meaning maximum of one pen).
hjlf

Answer:

The maximum area is therefore is 93750 ft²

Step-by-step explanation:

The given parameter are;

The a]length of fencing available = 1500 ft.

The perimeter of the figure = 9·x + 4·y

Therefore, 9·x + 4·y = 1500 ft.

The area of the figure = 6 × (x × y) = 3·x × 2·y

From the equation for the perimeter, we have;

9·x + 4·y = 1500

y = 1500/4 - 9/4·x = 375 - 9/4·x

y = 375 - 9/4·x

Substituting the value of y in the equation for the area gives;

Area = 3·x × 2·y = 3·x × 2·(375 - 9/4·x) = 2250·x - 27/2·x²

Area = 2250·x - 27/2·x²

The maximum area is found by taking the derivative and equating to zero as follows;

d(2250·x - 27/2·x²)/dx = 0

2250 - 27·x = 0

x = 2250/27 = 250/3

x = 250/3

y = 375 - 9/4·x = 375 - 9/4×250/3 = 187.5

The maximum area is therefore, 3·x × 2·y = 3 × 250/3 × 2 × 187.5 = 93750 ft²

The maximum area is therefore = 93750 ft.²

4 0
3 years ago
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