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masya89 [10]
1 year ago
11

the greatest common divisor of positive integers $m$ and $n$ is $8$. the least common multiple of $m$ and $n$ is $112$. what is

the least possible value of $m n$?
Mathematics
1 answer:
Tasya [4]1 year ago
8 0

Given the greatest common divisor and the least common multiple, the least possible value of mn is 896

<h3>How to determine the least possible value of mn?</h3>

The given parameters are:

M and N are positive integers

Greatest common divisor =  8

Least common multiple = 112

As a general rule;

The product of the greatest common divisor and the least common multiple of numbers represent the product of the numbers

This means that

mn = Greatest common divisor * Least common multiple

So, we have

mn = 8 * 112

Evaluate

mn = 896

Hence, the least possible value of mn is 896

Read more about least common multiple at

brainly.com/question/10749076

#SPJ1

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Solve the following pairs of simultaneous equations.
Sergeeva-Olga [200]

Answer and step-by-step explanation:

a) -4x + 5y = -9 (2)

2x + 3y = 21

Multiply the second equation by 2, you will get:

4x + 6y = 42 (1)

Use (1) plus with (2), you will get:

4x + (-4x) + 6y + 5y = -9 + 42

11y = 33

y = 33/11

y = 3

4x + 18 = 42

4x = 24

x = 6

b) 2x + 5y = -6

3x + 2y = 2

Multiply first equation by 3, you will get:

6x + 15y = -18 (1)

Multiply the second equation by 2 and you will get:

6x + 4y = 4 (2)

Subtract (1) by (2), we got:

6x -6x + 15y - 4y = -18 - 4

11y = -22

y = -22/11

y = -2

6x + 4y = 4

6x -8 = 4

6x = 12

x = 2

c) 2x - 2y = -4

5x + 4y = 17 (2)

Multiply the first euation by 2, we got:

4x - 4y = -4 (3)

Use (3) minus for (2), we get:

4x - 5x -4y + 4y = -4 - 17

-x = -21

x = 21

4x - 4y = -4

84 - 4y = -4

-4y = -4 + 84

-4y = 80

y = 80 / -4

y = -20

d) 2x - 3y = 6

4x - 5y = 9 (1)

Multiply the first equation by 2, we got:

4x - 6y = 12 (2)

Use (1) minus for (2), we got:

4x -4x - 5y - 6y = 9 -12

-11y = -3

y = -3/-11

y = 3/11

2x - 3y = 6

2x - 9/11 = 6

2x = 66/11 + 9/ 11

2x = 75/11

x = 75/11 * 1/2

x = 75 / 22

e) x/2 + y/3 = 2

x/4 + y/3 = 4

Use the first equation subtract the second equation, we got:

x/2 - x/4 + y/3 - y/3 = 2 - 4

2x/4 -x/4 = -2

x/ 4 = -2

x = -2 * 4

x = -8

x/2 + y/3 = 2

-8 / 2 + y/3 = 2

y / 3 = 2 + 4

y/3 = 6

y = 6*3

y = 18

f) x/3 + y/2 = 3/2 (1)

x/2 + y/5 = -1/2 (2)

I don't know how to solve this, sr

Hope this helped :3

3 0
3 years ago
5x + 2 y = 7<br> 4x + y = 8
dsp73
4y.
Is the answer
Hope this helps
8 0
2 years ago
How can I solve 4x^2 + 12x &gt; -x -3
Damm [24]

He have the following:

4x^2+12x>-x-3​

solving:

\begin{gathered} 4x^2+12x+x+3>-x-3+x+3​ \\ 4x^2+13x+3>0 \\ \text{factoring} \\ (4x+1)(x+3)>0 \\ (4x+1)>0\rightarrow4x+1-1>-1\rightarrow\frac{4x}{4}>-\frac{1}{4}\rightarrow x>-\frac{1}{4} \\ (x+3)

5 0
11 months ago
Find the complete quotient when P(x) is divided by the binomial following it.
Nutka1998 [239]

Answer:

Q(x) = x -11

Explanation:

<em>Please refer to the attached image for the Solution</em>

4 0
2 years ago
Fiona invested $1000 at 7% compounded continuously. At the same time, Maria invested $1100 at 7% compounded daily. How long will
Natali [406]

9514 1404 393

Answer:

  14,201 years

Step-by-step explanation:

The two compound interest formulas are ...

  A = P·e^(rt) . . . . . continuous compounding at rate r for t years

  A = P·(1 +r/365)^(365t) . . . . . daily compounding at rate r for t years

We went the amounts to be equal:

  1000·e^(0.07t) = 1100·(1+0.07/365)^(365t)

Dividing by 1000(1 +0.07/365)^(365t), we have ...

  ((e^0.07)/(1+0.07/365)^365)^t = 1.1

The base of the exponential on the left is ...

 ( e^0.07)/(1+0.07/365)^365 ≈ 1.00000671149321522

Taking logs, we have ...

  t×ln(1.00000671149321522) = ln(1.1)

  t = ln(1.1)/ln(1.00000671149321522) ≈ 0.09531018/(6.7114704·10^-6)

  t ≈ 14,201.09 . . . . . years

It will take about 14,201 years for the investments to be equal.

_____

<em>Additional comment</em>

The investment value at that time will be about $5.269·10^434. (That's a larger number than <em>anything</em> countable in the known universe, including energy quanta.)

These calculations are beyond the ability of many calculators, so might need to be carefully rewritten if the calculator only keeps 10 significant digits, or only manages exponents less than 100.

This shows that daily compounding is very close in effect to continuous compounding. It would take almost 150 years to make a difference of 0.1% in value.

4 0
3 years ago
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