All categories

3 years ago

Find the volume thank you for the help

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

all you need to do is multiply length times width times height.

Step-by-step explanation:

5 1/2 x 3= 16.5

16.5 x 2 1/4= 453.75

now just add both answers :)

I really hope this helps! <3 Good luck!

You might be interested in

In slope-intercept form, what is the equation of the line passing through the points (−4, 26) and (6, −4)?

vredina [299]

Answer:

y=-3x + 14 is your answer

Step-by-step explanation:

3 0

3 years ago

The range of this function

Monica [59]

Answer: C

Step-by-step explanation: The range of a function is all the outputs, or in this case all the values on the right side of the function. Therefore, we just look at what numbers are there and we find the range

7 0

3 years ago

What is the sign of addend with greater absolute value

Nady [450]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

-104=-8(k+8) <br><br> K = ?<br> Solution please if can?

maksim [4K]

Let's solve this question by step by step.

Layout equation.

−104=−8(k+8)

Step 1: Simplify both sides of the equation.

−104=−8(k+8)

−104=(−8)(k)+(−8)(8)(Distribute)

−104=−8k+−64

−104=−8k−64

Step 2: Flip the equation.

−8k−64=−104

Step 3: Add 64 to both sides.

−8k−64+64=−104+64

−8k=−40

Step 4: Divide both sides by -8.

-8k/-8=-40/-8

The answer for this problem is k=5.

5 0

3 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

4 years ago