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galben [10]
3 years ago
6

10 POINTS Find m arc DC

Mathematics
1 answer:
jasenka [17]3 years ago
7 0

Answer:

option a 48 correct

Step-by-step explanation:

see the solution

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Caculate the slope between the points <br> (9, 12) and (4, 17)
Scilla [17]
To calculate the slope you need to do (y2-y1)/(x2-x1). So you would get:
(17-12)/(4-9)
5/-5
=-1
Hope this helps.
3 0
3 years ago
I need help with this question
nydimaria [60]
I cant help i just needa answer something before i cant ask anything else
6 0
3 years ago
If you multiply 235 by 49, what will be the partial products?
Olenka [21]

Answer:

Step-by-step explanation:

(200+30+5)(40+9)

40*200 = 8000

40*30=   1200

40*5=200

9*200= 1800

9*30=270

9*5=45

8000+1200+200+1800+270+45 =11515

7 0
3 years ago
Read 2 more answers
Please help me .............
borishaifa [10]

Answer:

The first one.

Step-by-step explanation:

For something to be considered to be a graph, every x value must have 1 y value. It does not matter if y values are the same, but you MUST make sure there is ONLY ONE of each value. So for example the second one wouldn't be a function because -5 appears twice for the x values, but with different y values. This would mean when graphed, it would fail the vertical line test (if you put a vertical line anywhere on the graph you will only get one point).

8 0
3 years ago
Read 2 more answers
Graph the equation 3x+3y=−15 using the intercepts.
tatyana61 [14]

Answer:

To find the intercepts, equate one variable to

0

and solve for the other variable:

y-intercept

Set

x

to

0

and solve for

y

giving:

3

x

−

5

y

=

15

becomes:

(

3

⋅

0

)

−

5

y

=

15

0

−

5

y

=

15

−

5

y

=

15

−

5

y

−

5

=

15

−

5

−

5

y

−

5

=

−

3

y

=

−

3

or

(

0

,

−

3

)

x-intercept

Set

y

to

0

and solve for

x

giving:

3

x

−

5

y

=

15

becomes:

3

x

−

(

5

⋅

0

)

=

15

3

x

−

0

=

15

3

x

=

15

3

x

3

=

15

3

3

x

3

=

5

x

=

5

or

(

5

,

0

)

Next. we can plot the two points on the grid:

graph{((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Then, draw a line through the two points:

graph{(3x - 5y -15)((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

7 0
3 years ago
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