Answer:
<h2>an ostrich an ostrich an ostrich </h2>
... Organisms often preserved<span> by carbonization include </span>fish<span>, leaves and the woody tissues of plants.</span>
The frequency of allele is illustrated as the ratio of that specific allele in the population. As one knows that as the humans are diploid, so the total number of alleles is double of the total number of people in the population.
In order to determne the allele frequencies for A and B, there is a need to know that the persons with type A blood are homozygous AA, the persons with type AB blood are heterozygous AB, and the persons with type B blood are homozygous BB.
The frequency of A is:
2*(number of AA) + (number of AB) divided by 2 * (total number of individuals)
Therefore,
{2 * (200) + (75)} / 2 (200 +75 +25)
This comes out to be 475/600 = 0.792. Thus, p = 0.792.
Since, q is 1 - p
Then, q = 1 - 0.792 i.e 0.208.
Natural selection - in this case would be one of the fish survives and the one who gets less resources dies, due to the two species fighting for the same resource
Answer:
The correct answer is - sporophyte and gametophyte.
Explanation:
In seed producing plants such as gymnosperm and angiosperms the sporphytic part of life cycle is more dominant than the gametophytic part of life cycle. Sporophyte life cycle arise just after the formation of the zygote formation from fertilization of the gametes. The seeds are sporophytic structure that are dispersed to grow and be a full sporophytic plant with root, stem and leaves.
In mosses and ferns the case is different as there are no seed forming present the spores that are gametophytic as has n number of chromosome disperse to produce gametophytic plants that are comparatively small to sporophytic ones.
Thus, the correct answer is - sporophyte and gametophyte.
