I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6
Answer:
6 mi
Step-by-step explanation:
I think so it 6mi I need help
Answer:
x
Step-by-step explanation:
Answer:
The required expression is
.
The value of the expression when y=20 is 2.
Step-by-step explanation:
Consider the provided phase.
3 less than the quotient of a number y and 4
The quotient of a number y and 4 can be written as: 
Now 3 less than the quotient of a number y and 4 can be written as:

Hence, the required expression is
.
Now evaluate when y=20.
Substitute y=20 in above expression.



Hence, the value of the expression when y=20 is 2.
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.