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Fynjy0 [20]
2 years ago
7

Find the expression that is equivalent to the original exponential expression depicted below. Thank you!

Mathematics
2 answers:
svet-max [94.6K]2 years ago
5 0

Answer:

A

Step-by-step explanation:

you multiply the numbers and add the variables

Zigmanuir [339]2 years ago
5 0

\huge{ \rm{Answer:}}

A) {8xy}^{6}

multiply the <u>monomials</u>

Hope this helps^^

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There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
2 years ago
Select the solutions to the following inequality: |x| &lt; 7
Rasek [7]
|x| < 7
means x < 7 and x > -7

answer is -7 < x < 7
4 0
3 years ago
Morgan knows that 3 gallons of water weigh 25 pounds.<br> How much do 10 gallons of water weigh?
olga_2 [115]
The full answer would be 83.454 but you can just say 83 pounds. Both are right
8 0
3 years ago
A boy is flying a kite and has let out 300 feet of string. He notices that the angle the string makes with the ground is 38 degr
Bingel [31]

Answer:

height = 184.7 feet

Step-by-step explanation:

sin 38 = height/300

0.6157 = height/300

height = 184.7 feet

5 0
3 years ago
A dolphin jumps from the water at an initial velocity of 16 feet per second. The equation h + -16t^2 + 80t models the dolphin's
Dominik [7]

Answer:

100feet

Step-by-step explanation:

Given the height reached by a dolphin expressed by the equation is h = -16t^2 + 80t. At maximum height, the velocity is zero, hence;

v(t) = dh/dt = -32t + 80

0 = -32t + 80

32t = 80

t = 80/32

t = 2.5secs

Substitute t = 2.5 into the height formula h = -16t^2 + 80t

h = -16(2.5)^2 + 80(2.5)

h = -100+200

h = 100feet

Hence  the maximum height the dolphin jumps is 100feet

3 0
2 years ago
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