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The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height o

Anna11 [10]

The correct question is
The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height of 3/4 foot. The base of the rectangular prism is not a square and the width is greater than 2 feet. What is the length and width of the rectangular prism?

let
x-------> the length of the base of the rectangular prism
y-------> the width of the base of the rectangular prism

we know that
volume of the prism=area of the base*height
volume=48 ft³
height of the prism=3/4 ft

area of the base=volume/height--------> 48/(3/4)---> 48*4/3----> 64 ft²

area of the base=64 ft²
area of the base=x*y
64=x*y--------> equation 1

y=x+2--------> equation 2

substitute equation 2 in equation 1
64=x*[x+2]-----> 64=x²+2x------> x²+2x-64=0

using a graph tool----> to resolve the second order equation
see the attached figure

the solution is
x=7.062 ft
y=x+2-----> y=7.062+2-----> y=9.062 ft

the answer is
the length of the base of the rectangular prism is 7.062 ft
the width of the base of the rectangular prism is 9.062 ft

4 0

3 years ago

Write the slope-intercept form of the equation of the line described.4) through: (-5,0) , parallel to Y= -2/5x + 4

elixir [45]

To write the slope form quation

First; find the slope of

8 0

2 years ago

A spinner with 9 equal sections is numbered 1 through 9. The probability of spinning a 1 or a 9 is 2/9 .

gavmur [86]

7/9, because 1 - 2/9 = 7/9

5 0

4 years ago

Read 2 more answers

In a given figure if o is the centre of circle and oabc is a parallelogram find the value of abc

ahrayia [7]

From the given information, we get the value of ABC = 120°.

<h3>How to estimate the value of ABC?</h3>

Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.

Now, the radius of the circle exists

OA = OB = OC

Opposite sides of a parallelogram are equal

AB = OC and OA = BC

In ∆OAB,

OA = OB = AB and,

In ∆OCB,

OC = OB = BC

Therefore, ∆OAB and ∆OCB exist in equilateral triangles.

All angles of an equilateral triangle are equivalent to 60°.

Hence, ∠ABC = ∠OBA + ∠OBC

∠ABC = 60° + 60°

∠ABC = 120°

Therefore, the value of ∠ABC = 120°.

To learn more about parallelogram refer to:

brainly.com/question/24291122

#SPJ9

6 0

2 years ago

write the slope- intercept form of the equation of the line parallel to - x+5y=25, passing through the point (-5,-5). simplify

Olenka [21]

To find the equation of a line that is parallel to your original equation and goes through a certain point on a graph, here's what you need to know:
First you need to find the slope of your original equation.
To do that, you need to convert it to slope intercept form (y = mx+b).
Add the x over, and then divide everything by 5 to get the y by itself.
Here's what that would look like (without the small steps that I mentioned):
-x + 5y = 25
5y = x + 25
y = 1/5x + 5

That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.

Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
(h,k)
Then just substitute the values in and solve for y.
y - k = m(x - h)
y + 5 = 1/5(x + 5)
y + 5 = 1/5x + 1
y = 1/5x - 4

Your final answer is
y = 1/5x - 4
You can double check by using a graph. If the slopes are the same, the lines should be parallel.

I hope that helps. If anything didn't make sense, feel free to ask me.

5 0

3 years ago