What is the square root of 72/25x4

Mathematics

2 answers:

likoan [24]2 years ago

7 0

Ding it for the change

Afina-wow [57]2 years ago

6 0

Answer:

1.35764501988

Step-by-step explanation:

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Don't know what to do :\\

____ [38]

Answer: Choice A) 12x^2 - 48x + 21; all real numbers

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Work Shown:

(f * g)(x) = f(x) * g(x)
(f * g)(x) = ( f(x) ) * ( g(x) )
(f * g)(x) = ( -2x+7 ) * ( -6x+3 )
(f * g)(x) = -2x*( -6x+3 ) + 7*( -6x+3 )
(f * g)(x) = -2x*(-6x) - 2x*(3) + 7*(-6x) + 7*(3)
(f * g)(x) = 12x^2 - 6x - 42x + 21
(f * g)(x) = 12x^2 - 48x + 21

The domain is the set of all real numbers because we can plug in any number in for x, to get some output for y. There are no issues to worry about such as division by zero errors, square root of a negative number, etc.

6 0

3 years ago

Bag C is four times lighter than Bag A. Bag B is twice as heavy as Bag C. How much heavier is Bag A than Bag B ?

LiRa [457]

Answer:

Step-by-step explanation:

Current Weight Weight after adding Marbles

Giulio: 2x 2x + 10

Jim: x x + 5

You didn't post the options so hopefully you can determine the answer based on the info I provided above.

8 0

2 years ago

Which problem is modeled on the number line?<br> 3+(-6)<br> -3+(6)<br> 3+6<br> -3+6

kramer

Answer:3+(-6)

Step-by-step explanation:

5 0

3 years ago

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .