I assumed that 3 households are sampled.
Now, is the number in each of these households equal to 1, 3 and 8 people?
Next, the question says, samples of n=2 are randomly selected (with replacement) from these 3.
So are sample space is
11
13
31
33
18
81
38
88
83
88
This is done 9 times.
Is that how you understand the problem?
When they select the household with only 1 person, the variance is 0
When they select the household with 8 people, they variance will be from a discrete uniform distribution
Similarly for household with 3 individuals.
Y is 49
.....good luck.....
The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.
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Simplification</h3>
Question 1: a³ - 1000b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 1000 is the cube of 10
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(a - 10b) × (a² + 10ab + 100b²)
Question 2: 64a³ - 125b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 64 is the cube of 4
- 125 is the cube of 5
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(4a - 5b) • (16a² + 20ab + 25b²)
Learn more about simplification:
brainly.com/question/723406
#SPJ1
(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7
Answer:
16/3 or 5.3
Step-by-step explanation: