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3 years ago

What is the y intercept of the liner function that contains the points (4,1) (-3, -20)

Mathematics

1 answer:

myrzilka [38]3 years ago

8 0

Answer:

Step-by-step explanation:

To get the y-intercept, we need to get the slope first

Slope = y2-y1/x2-x1

Slope = -20-1/-3-4

slope = -21/-7

Slope = 3

Get the y-intercept. Substitute m = 3 and any point say (4, 1) into the expression y = mx+c

c is the y-intercept

1 = 3(4) + c

1 = 12 + c

c =1-12

c = -11

Hence the y-intercept is -11

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Step-by-step explanation:

From the question we are told that

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Now taking the exponent of both sides

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From the question we are told that

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Now integrating both sides

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Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

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Let $e^c = A$

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Now from the question we are told that

$x(0) = x_o$

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

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=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

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