You should add the two bases and muliply them with the height and then divide with 2
(14+18)×10÷2=160
Answer:
15/2
Step-by-step explanation:
The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds
What is the interquartile range of this data set? 2,5,9,11,18,30,42,55,58,73,81
Tcecarenko [31]
Answer:
I think it's 49 I'm sry if I'm wrong hope you luck
Step-by-step explanation:
