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Alex73 [517]
3 years ago
12

Which expressions are equivalent to 4(7/8y-4-3/8y+7)? Choose ALL that apply.

Mathematics
1 answer:
Georgia [21]3 years ago
5 0
2y+12 is the only correct answer I see
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Solve for x<br> -2/5x - 8/15x + 1/3x = -54<br> x=?
Ad libitum [116K]

Answer:

x=0

Step-by-step explanation:

solve for  x  by simplifying both sides of the equation, then isolating the variable. which got me x=0

3 0
3 years ago
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Troy's family is going to the beach for vacation. They plan to drive at the posted speed limit of 65 miles per hour and drive 5
Elena-2011 [213]
The answer is A) the number of miles
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3 years ago
Solve for x<br> y=7x−7z−9
juin [17]

y=7x−7z−9

7x = y + 7z + 9

 x = y/7 + z + 9/7

5 0
4 years ago
Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and
Jlenok [28]
We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

\frac{y}{x} = \frac{1}{8}  \\  \\ \Rightarrow x=8y \\  \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\  \\ \Rightarrow v=0

For the line with points (0, 0) and (1, 8), the equation is given by:

\frac{y}{x} = \frac{8}{1}  \\  \\ \Rightarrow y=8x \\  \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\  \\ \Rightarrow u=0

For the line with points (8, 1) and (1, 8), the equation is given by:

\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\  \\ \Rightarrow y-1=-x+8 \\  \\ \Rightarrow y=-x+9 \\  \\ \Rightarrow u+8v=-8u-v+9 \\  \\ \Rightarrow u=1-v

The Jacobian determinant is given by

\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\  \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\  \\ =63(-9)=|-576|=576
6 0
3 years ago
Alice had 3 1/4 pounds of flour at the beginning of the week. At the end of the week, she had 2 3/4 pounds. How much has she use
Evgen [1.6K]

Answer:

1 2/4

Step-by-step explanation:

you have to subtract they

4 0
3 years ago
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