Well, there is actually a formula for this kind of exercises:
n is the price the land had in the third year year
2500=n-nx0.6
2500=n(1-0.6)
2500=nx0.4
n=2500:0.4
n=6250
m is the price the land had in the second year
6250=m-mx0.6
6250=m(1-0.6)
6250=nx0.4
p=6250:0.4
p=15625
p is the price the land had in the first year
15625=p-px0.6
15625=p(1-0.6)
15625=px0.4
p=15625:0.4
p=39,062.5 <- this should be your answer. Hope this helps.
Answer:
A,B,C,D
Step-by-step explanation:
I say all of them because all of them are spelled correctly but if it incorrect i'm very sorry
In the first equation, moving 2x over gives "y = -2x-11". Placing this into the second equation gives "3x - 4(-2x-11) = 11", or "3x+8x+44 = 11", which can be reduced to "11x= -33" or "x = -3". Replacing the "x" with -3 in the first equation gives "-6 + y = -11" or "y = -5". This gives a solution of (-3, -5), or answer C.
The length of the other base is 18 meters.
