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dedylja [7]
3 years ago
12

How do I solve this problem

Mathematics
1 answer:
Anton [14]3 years ago
5 0
What does the rest of the problem say?

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What is the value of i^3?
Pavel [41]

Answer:

the answer is -i

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Evaluate: (ƒ − g)(−2)
klemol [59]

From the graph,

f(-2) = 0

and, g(-2) = 0

(ƒ − g)(−2)= f(-2)-g(-2) = 0

OPTION B is the correct answer

7 0
3 years ago
I need help.Write a stament or phrase to describe the numerial expression 150-200÷5
victus00 [196]
The answer is 13 , if i got i wrong sorry I tried my best

7 0
4 years ago
Round 776644 to the nearest thousand
prohojiy [21]

Answer:

776644 rounds to 777000    

Step-by-step explanation:

hundred thousand  ten thousand  thousand  hundred   tens  ones

 7                                   7                     6                6              4      4

We are rounding to the nearest thousand so we are rounding the first 6.  We need to look at the next 6 (the one in the hundreds place)  6>=5 so we will round the 6 in the thousands place up to 7

776644 rounds to 777000              

6 0
4 years ago
If n and k are positive integers, is n divisible by 6 ? (1) n = k(k + 1)(k – 1) (2) k – 1 is a multiple of 3.
xz_007 [3.2K]

Answer: yes, it is

Step-by-step explanation:

A number is divisible by 6 if it is divisible by 2 and 3 simultaniously.

n = k(k+1)(k-1)

If k-1 is a multiple of 3, n is divisible by 3, so one of the requirements is ok.

Now, if k-1 is a multiple of 3, it can be even or odd.

if k-1 is even, then it is divisible by 2 and as it is divisible by 3 as well, n is divisible by 6

if k-1 is odd, then k and k+1 is even, hence, divisible by 2.

As n = k(k+1)(k-1), n is also divisible by 6.

4 0
4 years ago
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