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3 years ago

Please help me with this problem

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer:

Step-by-step explanation:

$y+3=\sqrt{\frac{x}{16}+2 } \\y=\sqrt{\frac{x+32}{16} } -3\\y=\frac{1}{4} \sqrt{x-(-32)} +(-3)\\so ~C$

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Which attribute is NOT always true for a rhombus?

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Step-by-step explanation:

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You win an online auction for a toy. Your winning bid of $35 is 70% of your maximum bid. How much more were you willing to pay f

luda_lava [24]

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If you divide 35 by 7, you will find what 10% of your maximum bid is.
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3 years ago

Graph -5x + 2 > 3y and 3x-4y <3

Sladkaya [172]

Answer:

Below!

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Solve for y.

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3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

$x = 3 + 4\sqrt{3} = 9.928(4s.f.)$

$x = 3 - 4\sqrt{3} = -3.928(4s.f.)$ (Length can't be negative)

∴ $x = 3 + 4\sqrt{3}$

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2 years ago

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Please help me with this problem​

Please help me with this problem