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katovenus [111]
2 years ago
9

Which algebraic expression is equivalent to w+w+w+3+2

Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
3 0

Answer:

5+3w

Step-by-step explanation:

make it braintliest please

ss7ja [257]2 years ago
3 0

Answer:

w^3+5

Step-by-step explanation:

I am pretty sure you would just combine like terms and then add them together.

I hope this helps u out...

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The marketing department of a sports supply store wants to estimate the percentage of adults in the town who belong to a gym.
velikii [3]
A) If you only sample people in a sports supply store, your sample will be biased.  People in a sports supply store are more likely to be people that belong to a gym.
B) While it does not have necessarily the same amount of bias as sampling people in the sports supply store, people that go to a park are generally more likely to be people that exercise or have a gym membership.
C) Taking a random sample of people in town is a good way to get a non-biased sample.  They are not necessarily predisposed to answer your question one way or another.
D) For the same reason as choice A, this is a biased sample.

C is the best choice.
4 0
2 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
2 years ago
African elephants can eat up to 500 pounds of vegetation in one day. How many pounds of vegetation could an elephant eat in a we
Murrr4er [49]

Answer:

they would eat 3500 pounds of food in 1 week

Step-by-step explanation:

its simple math just multiply 500 by 7 and you would get 3500

5 0
2 years ago
Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx
yawa3891 [41]

\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}

Expand the numerator as

x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2

Then in the limit,

\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}

3 0
2 years ago
The deck of cards is well shuffled. the cards are picked from the top of the deck. how many cards do you expect to pull from the
S_A_V [24]
There are at least 4 queens in a deck of cards (spades, club, diamond, and hearts) in each of the groups there thirteen cards. given that 13(4) is 52 cards in total 48 of them Are not queen. So 48/4 is 12. I divided them because the four groups. I think it should be 12 cards.
6 0
3 years ago
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