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3 years ago

How to solve the inequalities 2x-3 < 3x+7

Mathematics

2 answers:

timama [110]3 years ago

7 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form: x > -10

Interval Notation: (-10, ∞)

Step-by-step explanation:

x > -10 is. most likely to b the answer. hopes this helps

Andrej [43]3 years ago

6 0

Answer: X > -10

Step-by-step explanation:

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What is the factored form of 250x^3 − 16? A. 2(5x − 2)(25x2 + 10x + 4) B. 2(5x + 2)(25x2 − 10x + 4) C. (5x − 2)(25x2 + 10x + 4)

Juli2301 [7.4K]

Answer:

The choose A.

$250 {x}^{3} - 16 \\ 2(5x - 2)(25 {x}^{2} + 10x + 4)$

I hope I helped you^_^

5 0

2 years ago

Why 3/6 is not equivalent to 2/9

Westkost [7]

Because 3/6 equals 1/2 and 2/9 equals 1/3

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3 years ago

Read 2 more answers

Solve.<br> y =-2x + 9<br> y =4x-3

sammy [17]

Answer:

X= 2 Y=5

Step-by-step explanation:

Set them equal

-2x+9=4x-3 add -2x to both sides and -3 to both sides

12=6x then divide by 6

x=2

plug in 2 to either equation and solve for Y.

Y=-2(2)+9

Y=5

5 0

2 years ago

Write the next three terms of the arithmetic sequence.

Inga [223]

Answer:

36, 44, 52

Step-by-step explanation:

Just add 8 to 28 = 36

Add 8 to 36 = 44

Add 8 to 44 = 52

8 0

3 years ago

Read 2 more answers

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .